What is the sum of oxidation numbers for a polyatomic ion?

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Multiple Choice

What is the sum of oxidation numbers for a polyatomic ion?

Explanation:
Oxidation numbers are chosen so that the algebraic sum of all atoms’ oxidation numbers in a species equals the overall charge of that species. In a polyatomic ion, that total must match the ion’s charge. For example, in nitrate NO3–, oxygen is almost always –2, giving –6 from three oxygens; to reach the –1 charge of the ion, nitrogen must be +5. In sulfate SO42–, four oxygens contribute –8, so sulfur must be +6 to give the overall –2 charge. This shows that the sum of the oxidation numbers in a polyatomic ion equals the ionic charge, not zero or any other quantity like the number of atoms or the total valence electrons.

Oxidation numbers are chosen so that the algebraic sum of all atoms’ oxidation numbers in a species equals the overall charge of that species. In a polyatomic ion, that total must match the ion’s charge. For example, in nitrate NO3–, oxygen is almost always –2, giving –6 from three oxygens; to reach the –1 charge of the ion, nitrogen must be +5. In sulfate SO42–, four oxygens contribute –8, so sulfur must be +6 to give the overall –2 charge. This shows that the sum of the oxidation numbers in a polyatomic ion equals the ionic charge, not zero or any other quantity like the number of atoms or the total valence electrons.

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